Question

Please answer this question​

Answer 1

$x = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \: \: \: \: y = \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ xy = 1 \\ x + y = \frac{ \sqrt{3 } + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } + \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ = \frac{( { \sqrt{3} + \sqrt{2} })^{2} + ( { \sqrt{3} - \sqrt{2} })^{2} }{( \sqrt{3} )^{2} - ( { \sqrt{2} })^{2} } \\ = \frac{2(( { \sqrt{3} })^{2} + ( { \sqrt{2} })^{2} )}{3 - 2} \\ = 2(3 + 2) \\ = 2 \times 5 \\ = 10 \\ {x}^{2} + {y}^{2} = ( {x + y})^{2} - 2xy \\ = ( {10})^{2} - 2 \times 1 \\ = 100 - 2 \\ =98$

Answer 2

Answer:

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