Math, asked by sonialalit17128, 2 months ago

please answer this question​

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Answers

Answered by keerthana982006
0

Answer:

i dono

Step-by-step explanation:

Answered by 12thpáìn
3

Solve the Equation :

  • { \sf \dfrac{9p + 7}{2}  -   \left(1 + p -  \dfrac{p - 2}{7} \right) = 35}

Step by step Explanation

{  \:  \:  \:  \:  \:  :  \implies\sf \dfrac{9p + 7}{2}  -   \left(1 + p -  \dfrac{p - 2}{7} \right) = 35}

{  \:  \:  \:  \:  \:  :  \implies\sf \dfrac{9p + 7}{2}  -   \left( \dfrac{7 +7 p -  (p - 2)}{7} \right) = 35}

{  \:  \:  \:  \:  \:  :  \implies\sf \dfrac{9p + 7}{2}  -   \left( \dfrac{7 +7 p -  p  +  2}{7} \right) = 35}

{  \:  \:  \:  \:  \:  :  \implies\sf \dfrac{9p + 7}{2}  -    \dfrac{9+6 p }{7}  = 35}

{  \:  \:  \:  \:  \:  :  \implies\sf \dfrac{7(9p + 7) - 2(9 + 6p)}{2 \times 7}    = 35}

{  \:  \:  \:  \:  \:  :  \implies\sf \dfrac{63p + 49 - 18  -  12p}{14}    = 35}

{  \:  \:  \:  \:  \:  :  \implies\sf 51p + 31    = 35 \times 14}

{  \:  \:  \:  \:  \:  :  \implies\sf 51p + 31    =4 90}

{  \:  \:  \:  \:  \:  :  \implies\sf 51p    = 490- 31}

{  \:  \:  \:  \:  \:  :  \implies\sf \cancel{ 51} ^{1}   p  = \cancel{ 459}} ^{9}

{  \:  \:  \:  \:  \:  :  \implies\bf p    = 9} \\  \\  \\

Verification:

{~~~~~~~~~~ \mapsto\tiny \sf \dfrac{9p + 7}{2}  -   \left(1 + p -  \dfrac{p - 2}{7} \right) = 35}

  • Putting p=9

{~~~~~~~~~~\mapsto \tiny \sf \dfrac{9 \times 9 + 7}{2}  -   \left(1 + 9 -  \dfrac{9 - 2}{7} \right) = 35}

{~~~~~~~~~~\mapsto \tiny \sf \dfrac{81+ 7}{2}  -   \left(10 -  \dfrac{7}{7} \right) = 35}

{~~~~~~~~~~\mapsto \tiny \sf \dfrac{88}{2}  -   \left(10 -  1 \right) = 35}

{~~~~~~~~~~\mapsto \tiny \sf 44    - 9 = 35}

~~~~~~~~~~{\mapsto \tiny \sf 35= 35} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:~~~~~~~~~  \:  \:  \:  \:  \\  \bf verified\\\\

Step To Solve Liner Equation

In One Variable.

Step 1: Simplify each side, if needed.

Step 2: Use Add./Sub. Properties to move the variable term to one side and all other terms to the other side.

Step 3: Use Mult./Div. Properties to remove any values that are in front of the variable.

Step 4: Check your answer.

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