Question

please answer this question
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Answer 1

Answer:

hey your answer is as follows

so pls mark it as brainliest

Step-by-step explanation:

so now for parallelogram bdef

as opposite sides of parallelogram are equal

bf=ed }

fe=bd } (1)

similarly for parallelogram dcef

fd=ec }

ef=cd } (2)

now considering triangle bdf and triangle dec

bf=ed

fd=ec from (1) and (2)

also angle bdf=angle edc (common angle)

thus by S.A.S Test we can prove triangle bdf and dec as congruent

thus bd=dc (c.s.c.t)

thus proved