Question

please answer this question​

Answer 1

Answer:

Hope it will help you....

Answer 2

Answer:

I am only able to see the $(ii)$, $(iii)$ and $(iv)$ questions clearly and will only be able to answer those $3$

$(ii)$ $32^{\frac{2}{5} }$

    We can write $32$ as a product of its factors

    ⇒ $(2*2*2*2*2)^{\frac{2}{5} }$

    ⇒ $(2^{5} )^{\frac{2}{5} }$

    We know that $(a^{m})^{n} = a^{m*n}$

    ⇒ $2^{5*\frac{2}{5} }$

    $5's$ cancel each other out

    ⇒ $2^{2}$

    ⇒ $2*2 = 4$

$(iii)$ $16^{\frac{3}{4}}$

      We can write $16$ as a product of its factors

      ⇒ $(2*2*2*2)^{\frac{3}{4} }$

      ⇒ $(2^{4})^{\frac{3}{4} }$

      We know that $(a^{m})^{n} = a^{m*n}$

      ⇒ $2^{4*\frac{3}{4} }$

      $4's$ cancel each other out

      ⇒ $2^{3}$

      ⇒ $2*2*2 = 8$

$(iv)$ $125^{\frac{-1}{3} }$

     We can write $125$ as a product of its factors

     ⇒ $(5*5*5)\frac{-1}{3}$

     ⇒ $(5^{3} )\frac{-1}{3}$

     We know that $(a^{m})^{n} = a^{m*n}$

     ⇒ $5^{3*\frac{-1}{3} }$

     $3's$ cancel each other out

     ⇒ $5^{-1}$

     We know that $a^{-1} = \frac{1}{a}$

     ⇒ $\frac{1}{5}$