Question

please answer this question​

Answer 1

Answer:

Let the distance between the spaceship and the ground station be 'S' .

Then, S=vt

where, v= speed of signal =3×10⁸

m/s

t= time taken =5min=5×60s=300s

∴s=3×10⁸ ×300=9×10¹⁰ m

Answer 2

Given

• A signal from a spaceship reached the ground in 5 minutes.
• The signal travels at the speed of light, that is, 3 × 10⁸ ms⁻¹

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To Find

• The distance of the spaceship from the ground station.

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Solution

Time taken → 5 minutes = 5 × 60 = 300 seconds

Speed → 3 × 10⁸ ms⁻¹

Distance → ?

Since,

Speed = Distance ÷ Time

So,

Distance = Speed × Time

Distance = 300 × 3 × 10⁸

Distance = 3 × 100 × 3 × 10⁸

Distance = 3 × 10² × 3 × 10⁸

Distance = (3 × 3) × (10² × 10⁸)

[Law of Exponent ⇒ $\sf a^{m}\times a^{n} = a^{m+n}$]

Distance = 9 × (10²⁺⁸)

Distance = 9 × 10¹⁰ meters

∴ The distance of the spaceship from the ground station is 9 × 10¹⁰meters.

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