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- Sol: Let CP of A = Rs x SP of A = (72/100) x = 0.72 x [There is a loss of 28%] CP of B including the cost of repairs= (0.72x + 1680) SP of B = Rs 35910 Profit Percentage = (0.72x + 1680) = 12.5 (3423 -0.72x) /
- Sol: Let CP of A = Rs x SP of A = (72/100) x = 0.72 x [There is a loss of 28%] CP of B including the cost of repairs= (0.72x + 1680) SP of B = Rs 35910 Profit Percentage = (0.72x + 1680) = 12.5 (3423 -0.72x) /12.5% [(35910) - (0.72x + 1680)] x 100 /
- Sol: Let CP of A = Rs x SP of A = (72/100) x = 0.72 x [There is a loss of 28%] CP of B including the cost of repairs= (0.72x + 1680) SP of B = Rs 35910 Profit Percentage = (0.72x + 1680) = 12.5 (3423 -0.72x) /12.5% [(35910) - (0.72x + 1680)] x 100 /(0.72x + 1680) = (125/100) 3423000
- Sol: Let CP of A = Rs x SP of A = (72/100) x = 0.72 x [There is a loss of 28%] CP of B including the cost of repairs= (0.72x + 1680) SP of B = Rs 35910 Profit Percentage = (0.72x + 1680) = 12.5 (3423 -0.72x) /12.5% [(35910) - (0.72x + 1680)] x 100 /(0.72x + 1680) = (125/100) 3423000- 72x = 9x + 210003423000 - 21000
- Sol: Let CP of A = Rs x SP of A = (72/100) x = 0.72 x [There is a loss of 28%] CP of B including the cost of repairs= (0.72x + 1680) SP of B = Rs 35910 Profit Percentage = (0.72x + 1680) = 12.5 (3423 -0.72x) /12.5% [(35910) - (0.72x + 1680)] x 100 /(0.72x + 1680) = (125/100) 3423000- 72x = 9x + 210003423000 - 21000= 9x + 72x3402000 = 81x ⇒ x = 42000 Therefore, cost price of A is Rs 42,000.
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Answer:
Let C.P of bikes =Rs.x
⇒ Gaurav sold the bike at y=x−10028x=10072x
C.P for vikas =10072x+1680
Profit =C.PS.P−C.P×100⇒100125=C.Ps.p−1⇒100112.5=C.P35910
⇒C.P=31920⇒10072x=30240⇒x=Rs.42000
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