Question

please answer this question​

Answer 1

Answer:

for fiinding the value of x, y, z

we have to find the value of y frst

so,

we know tht, sum of all angles of triangles = 180 °

90 + 60+y = 150

y = 180-150 = 30

y = 30°

So now we have to find the value of x, z

now value of x, z

we know tht x, y, z forns linear pair

so linera pair = 180°

30+x+z = 180

180 - 30 = 150

so value of x, z = 150/2 =

75

so value of x= 75°

so value of z= 75°

Step-by-step explanation:

pls mark me brainliest

Answer 2

Solving :

$\\ \large \sf \: pq \parallel bc \\ \\ \large \sf \angle acb = 90 \degree \: ( right \: \: angle) \\ \\ \large \sf \angle abc = 60 \degree \: (given) \\ \\ \large \mapsto\underline{ \sf \:angle \: \: sum \: \: property : } \\ \\ \large \rm \: sum \: \: of \: \: interior \: \: angles = 180\degree \\ \\ \large \tt : \implies \angle y + \angle b + \angle c = 180 \degree \\ \\ \large \tt : \implies \angle y+ 60 \degree + 90 \degree = 180 \degree \\ \\ \large \tt : \implies \angle y+ 150 \degree = 180 \degree \\ \\ \large \mapsto\underline{ \sf \:transposing \: \: terms : } \\ \\ \large \tt : \implies \angle y = 180 \degree - 150 \degree \\ \\ \large \tt \therefore \underline{\underline{ \angle y = 30 \degree}}$

$\large \rm \angle \: z = 60 \degree \: (corresponding \: \: angles) \\ \\ \large \tt \implies \: \angle \: z + \angle \: y = 30 \degree + 60 \degree \\ \\ \large \tt \implies \: \angle \: z + \angle \: y =90 \degree \\ \\ \large\rm \mapsto \: angles \: \: along \: \: staright \: \: line \\ \large \rm \: \: \: \: \: \: = 180 \degree\\ \\ \large \tt \implies \: \angle \: x + \angle \: z + \angle \: y =180 \degree \\ \\ \large \tt \implies \: \angle \: x + 90 \degree =180 \degree \\ \\\large \tt \implies \: \angle \: x = 180 \degree - 90 \degree \\ \\\large \tt \therefore \underline{\underline{ \angle \: x = 90 \degree}}$