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Given v=20a
(tent. acc.)=10m/se
2a(c)=?
a(c)=V*2/R =
20×20/10
=40 m/sec*2
=40a(net)
=(10x10+40×40)^2
=500^2
=m/sec^2
(tent. acc.)=10m/se
2a(c)=?
a(c)=V*2/R =
20×20/10
=40 m/sec*2
=40a(net)
=(10x10+40×40)^2
=500^2
=m/sec^2
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Answered by
2
Given v=20a
(tent. acc.)=10m/se
2a(c)=?
a(c)=V*2/R =
20×20/10
=40 m/sec*2
=40a(net)
=(10x10+40×40)^2
=500^2
=m/sec^2
MARK AS BRAINLIST
(tent. acc.)=10m/se
2a(c)=?
a(c)=V*2/R =
20×20/10
=40 m/sec*2
=40a(net)
=(10x10+40×40)^2
=500^2
=m/sec^2
MARK AS BRAINLIST
Answer
answer
Tanya didi
Sarang bhaiya
Anyone
didi
wait
what is S.AV.
the average velocity is 0 because displacement doesn't take place
velocity=displacement/time
velocity=displacement/time
hey here is your answer
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