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Answered by
9
Find the annual amount and compound interest on ₹50000 for 1 1/2 years at 8% per annum.
It is given that,
- Principal = 50000
- Rate of interest (r) = 8% p.a. = 4% semi-annually
- Period (n)= 1 1/2 years = 3 semi-annually
We know that,
- Amount = P(1+r/100)n
- Substituting the values = 50000(1+4/100)³
- By further calculation = 50000(26/25)³
- = 50000×26/25×26/25×26/25
- = 56243.20
Here,
- Compound interest = A - P
- Substituting the values = 56243.20−50000
- = 6243.20
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hope it's helpful!
Answered by
27
Your answer :-
It is given that,
Principal = 50000
Rate of interest (r) = 8% p.a. = 4% semi-annually
Period (n)= 1 1/2 years = 3 semi-annually
We know that,
Amount = P(1+r/100)n
Substituting the values = 50000(1+4/100)³
By further calculation = 50000(26/25)³
= 50000×26/25×26/25×26/25
= 56243.20
Here,
Compound interest = A - P
Substituting the values = 56243.20−50000
= 6243.20
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Hope it helps ♡࿐
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