Question

please answer this question​

Answer 1

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Answer 2

Answer:

The tension in the lower wire T 2 =150N (solved earlier)

Also sinθ= 54 and cosθ=53

(solved earlier)

Given : m=4 kg, T1

=200 N

Horizontal direction : ma r =T1 cosθ+T2 cosθ

∴ mrw^2 =(T1+T2 )cosθ where r=OA=3 m

∴ 4×3w^2

=(200+150)× 53

⟹w= 4.18 N

Using 2πf=w

∴ 2πf=4.18

⟹f=0.67 rps

⟹ f=0.67×60=39.6 rpm

Explanation:

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