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14. let breadth=X
let length = X+4
New, let breadth =X+3
let length = X+7
then,
(X+7)(X+3)=81+(X)(X+4)
x^2+3x+7x+21=81+x^2+4x
10x+21=81+4x
10x-4x=81-21
6x=60
x=60/6=10
hence breadth = 10
length = 10+4=14
16.Sum of two numbers=2490
x+y=2490
6.5x%+8.5x%=2490
15x/100=2490
15x=2490*100
x = 2490*100/15
= 166*100
= 16600
1st number= 6.5%x
= 6.5/100*16600
= 1079
2nd number=8.5%x.
= 8.5/100*16600
= 1411
Hope it helps you.....
let length = X+4
New, let breadth =X+3
let length = X+7
then,
(X+7)(X+3)=81+(X)(X+4)
x^2+3x+7x+21=81+x^2+4x
10x+21=81+4x
10x-4x=81-21
6x=60
x=60/6=10
hence breadth = 10
length = 10+4=14
16.Sum of two numbers=2490
x+y=2490
6.5x%+8.5x%=2490
15x/100=2490
15x=2490*100
x = 2490*100/15
= 166*100
= 16600
1st number= 6.5%x
= 6.5/100*16600
= 1079
2nd number=8.5%x.
= 8.5/100*16600
= 1411
Hope it helps you.....
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