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Hiiiii! Here is your answer........
As PQ ll XY
y:z = 4:5
Solution :-
1]PQ ll XY, t is the transversal
Hence, angle x is congruent to angle z
angle z = 5x
Hence, angle X = 5x
2] PQ ll RS
angles x and y are interior angles
x +y =180°
5x+4x=180
9x=180
x=180/9
x=20°
3] Hence,
Angle x = 5×x =5×20=100°
Angle y=4×x=4×20=80°
Angle z=5×x=5×20=100°
4] angle y+m=180°..................Angles in linear pair
y+m=180
80+m=180
m=180-80
m=100°
Hope it helps you!
As PQ ll XY
y:z = 4:5
Solution :-
1]PQ ll XY, t is the transversal
Hence, angle x is congruent to angle z
angle z = 5x
Hence, angle X = 5x
2] PQ ll RS
angles x and y are interior angles
x +y =180°
5x+4x=180
9x=180
x=180/9
x=20°
3] Hence,
Angle x = 5×x =5×20=100°
Angle y=4×x=4×20=80°
Angle z=5×x=5×20=100°
4] angle y+m=180°..................Angles in linear pair
y+m=180
80+m=180
m=180-80
m=100°
Hope it helps you!
kanisha35:
Thank you so much for the correct answer
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