Question

please answer this question

Answer 1

p= - 2

q = - 1

r = 3

=> 3 p^2 q + 5pq^2 + 2pqr = 3(-2)^2 (-1) + 5 (-2)(-1)^2 + 2 (-2)(-1)(3)

= 3 (4)(-1) + (5)(-2)(1) + (2)(2)(3)

= - 12 - 10 + 12

= - 10

Answer 2

Given,
P=-2
Q=-1
R=3
To find,
3p²q+5pq²+2pqr
=PQ(3p+5q+2r)
Putting value
=(-2×-1)(3×-2+5×-1+2×3)
=2(-6-5+6)
=2×-5
=-10
(ÆÑẞWĒR)