Question

please answer this question

Answer 1

$\huge{\boxed{\boxed{\underline{\mathfrak{Answer \ :}}}}}$

$\bf{To \ Find \ :}$

• Product of $\sf{\frac{-7}{5}}$ and the additive inverse of $\sf{1 \frac{4}{21}}$

$\bf{Explanation \ :}$

So, first we will find the additive inverse of $\sf{1 \frac{4}{21}}$, In additive inverse the sign of the number or fraction is changed.

$\therefore$ Additive inverse of $\sf{\frac{-7}{5}}$ is $\sf{\frac{7}{5}}$.

______________[Now]

Now we have to find the product of $\sf{\frac{7}{5}}$ and $\sf{1 \frac{4}{21}}$ ($\sf{\frac{25}{21}}$).

$\sf{\implies \frac{\cancel{7}}{\cancel{5}} \times \frac{\cancel{25}}{\cancel{21}}} \\ \\ \sf{\implies \frac{5}{3}}$

$\large{\boxed{\boxed{\sf{Answer \ : \frac{5}{3}}}}}$