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Let the triangle be ∆ABC
In ∆ABC,
<CAB = y°
<ABC = 90° (Right angle)
<BCA = 70° (Given)
Sum of all the angles of a triangle = 180°
So, <CAB + <ABC + <BCA = 180°
y + 90° + 70° = 180°
y + 160° = 180°
y = 180° - 160°
y = 20°
Please mark my answer as brainliest.
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