Question

please answer this question​

Answer 1

Answer:

Given: seg CO ≅ seg OB

and ∠ACO ≅ ∠DBO

Now, in ∆ACO and ∆DBO,

∠ACO ≅ ∠DBO (given)

seg OC ≅ seg OB (given)

∠AOC ≅ ∠DOB (vertically-opposite angles)

So,∆ACO ≅ ∆DBO (ASA congruency test)

Then,

∠OAC ≅ ∠ODB (c.a.c.t)

seg AC ≅ seg DB (c.s.c.t)

seg AO ≅ seg DO (c.s.c.t)

Answer 2

Answer:

ΔABC ≅ ΔDCB by SSS

Step-by-step explanation:

AB = DC (Given)

AC = DB (Given)

BC = BC (Common side)

So by SSS[Side-Side-Side] criteria, ΔABC ≅ ΔDCB

For additional information you can also use this proved statement with CPCT to show that -

∠ABC = ∠DCB

∠BCA = ∠CBD

∠CAB = ∠BCD

Cheers :)