Math, asked by Architjoshi789, 1 year ago

please answer this question

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Answered by khush61
0

1) = (2x - 1)(x + 5) \\  = 2x(x) + 2x(5) - x - 5 \\  =  {2x}^{2}  + 10x - x - 5 \\  = 2 { x}^{2}  - 5x - 5
(7 -  {x}^{2} )(2x + 4) \\  = 7(2x) + 7(4) - 2x( {x) }^{2}  - 4 {x}^{2}  \\  = 14x + 28 -  {2x}^{3}  - 4 {x}^{2}  \\  =  - 2 {x}^{3}  - 4 {x}^{2}  + 14x + 28
(x - 3y)(5x + y) \\ (x)5x + xy - 5x(3y) - 3 {y}^{2}  \\ 5 {x}^{2}  + xy - 15xy - 3 {y}^{2}
(m - 4n)( - m + 3n) \\  -  {m}^{2}    +  3mn + 4mn - 12 {n}^{2}  \\  -  {m}^{2}  - 12 {n}^{2}  + 7mn
Answered by archit460
0
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