Question

please answer this question​

Answer 1

$\sf log_{a}(b) \times log_{b}(c) \times log_{c}(a)$

$\sf \implies \: \dfrac{ log_{c}(b) }{ log_{c}(a) } \times log_{b}(c) log_{c}(a)$

$\sf \implies \: \dfrac{log_{c}(b) }{ \cancel{ log_{c}(a)} } \times log_{b}(c) \cancel{ log_{c}(a) }$

$\sf \: Use \: log_{b}(a) × log_{a}(b) = 1 \: to \: simplify$

$\implies \: 1$

Hence, proved