Question

Please answer this question​

Answer 1

Answer:

(i)Here, AB = 18 cm, BC = 10 cm, AF = 6 cm, AE = 10 cm and BE = 8 cm Area of shaded portion = Area of rectangle ABCD – (Area of Δ FAE + area of Δ EBC) = (AB x BC) – (1/2 x AE x AF + 1/2 x BE x BC) = (18 x 10) – (1/2 x 10 x 6 +1/2 x 8 x 10) = 180 – (30 + 40) = 180 – 70 = 110 cm2

(ii) Here, SR = SU + UR = 10 + 10 = 20 cm, QR = 20 cm PQ = SR = 20 cm, PT = PS – TS = 20 – 10 cm TS = 10 cm, SU = 10 cm, QR = 20 cm and UR = 10 cm Area of shaded region = Area of square PQRS – Area of Δ QPT – Area of Δ TSU – Area of Δ UQR = (SR x QR) - 1/2 x PQ x PT – 1/2 x ST x SU – 1/2 x QR x UR = 20 x 20 –1/2 x 20 x 10 –1/2x 10 x 10 –1/2 x 20 x 10 = 400 – 100 – 50 – 100 = 150 cm2