Question

please answer this question

Answer 1

Given coordinates of A and C are (3,6) and (-1,2).

Slope of AC = (y2 - y1)/(x2 - x1)

= > (2 - 6)/(-1 - 3)

= > (-4)/(-4)

= > 1.

= > m1.

We know that diagonal of a rhombus bisect at right angle.

= > m1 * m2 = -1

= > 1 * m2 = -1

= > m2 = -1.

Now,

Coordinates of mid point of AC = [(x1 + x2)/2, (y1 + y2)/2]

= > [(3 - 1)/2, 6 + 2)/2]

= > (1,4).

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Equation of BD :

= > y - y1 = m(x - x1)

= > y - 4 = -1(x - 1)

= > y - 4 = -x + 1

= > x + y - 5 = 0.

Hope this helps!