Question

please answer this question!

Answer 1

Hey Mate!!

Here Is Answer To Your Question

It is an acid solution - The p-H will always be below 7.00. It cannot be above 7.00 because then it would be a basic solution
The []H+] of pH 6.00 solution = 10^-pH
[H+] = 10^-6.00

At these very low concentrations ( especially after you have diluted the solution further with water ) the contribution of H+ from the autoionisation of the water has to be taken into account
You can calculate the [H+] in the final solution using a shortcut method usinf the dilution equation.
C1V1 + C2V2 = C3V3
You mix 1.0mL of the [H+] = 10^-6 M solution with 1000mL of 10^-7M solution
1.00*10^-6 + 1000* 10^-7 = 1000*C3
10^-6 + 10^-4 = 1000C3
C3 = 1.01*10^-4 /1000
C3 = 1.01*10^-7M
C3 = []H+] in the final solution
pH = - log [H+]
pH = -log (1.01*10^-7)
pH = 6.99

Regards Vishal________(BhamBhamBhole)

Answer 2

A solution of ph=6 has concentration 10-6 M.( 10 to the power of-6 M) . If it is diluted 1000 times, it becomes 10-6/1000 = 10-9 M. Water has a pH = 7. Thus, [H3O+] in water = 10-7 M.  Now, the [H3O+] in dilute acidic solution will approach 10-7 M. The concentration can not become less than 10-7 M due to dissociation of water to H3O+. So, pH of resulting solution will be approx. 6.96.