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Hey mate here is your answer ⤵⤵⤵
Sol: Let the number of mangoes be x.when x ÷ 2 leaves remainder as 1. when x ÷ 3 leaves remainder as 2. when x ÷ 4 leaves remainder as 3. when x ÷ 5 leaves remainder as 4. when x ÷ 6 leaves remainder as 5. when x ÷ 7 leaves remainder as 0. ⇒ x is divisible by 7. The remainder in each case is 1 less than the divisor. ⇒ (x + 1) is the LCM of 2, 3, 4, 5 and 6. LCM of 2, 3, 4, 5 and 6 = 60. If x + 1 = 60, then x = 59. But 59 is not divisible by 7. If x + 1 = 120, then x = 119. 119 is divisible by 7 also it satisfies all the conditions. Hence the number of mangoes = 119.✔✔
❤hope it helps you ❤
♠please mark as BRAINLIEST.♠
Sol: Let the number of mangoes be x.when x ÷ 2 leaves remainder as 1. when x ÷ 3 leaves remainder as 2. when x ÷ 4 leaves remainder as 3. when x ÷ 5 leaves remainder as 4. when x ÷ 6 leaves remainder as 5. when x ÷ 7 leaves remainder as 0. ⇒ x is divisible by 7. The remainder in each case is 1 less than the divisor. ⇒ (x + 1) is the LCM of 2, 3, 4, 5 and 6. LCM of 2, 3, 4, 5 and 6 = 60. If x + 1 = 60, then x = 59. But 59 is not divisible by 7. If x + 1 = 120, then x = 119. 119 is divisible by 7 also it satisfies all the conditions. Hence the number of mangoes = 119.✔✔
❤hope it helps you ❤
♠please mark as BRAINLIEST.♠
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