please answer this question 6 or 7
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this is your answer
6) Given = (i) ABCD is a ractangle
(ii) BC = 6 cm ( therefore AD = 6 cm )
(iii) AB = 8 cm
solution = in ractangle ABCD
angle A = 90° ( right angle )
angle B = 90°
angle C = 90°
angle D = 90°
in triangle ABD
angle A = 90°
by Pythagorean theorem
hypotenuse ^2 = perpendicular ^2 + base ^2
= (BD) ^2 = (AB)^2 + (AD)^2
= (BD)^2 = 8^2 + 6^2
= (BD)^2 = 64 + 36
= (BD)^2 = 100
= BD = √100
= BD = 10 cm
hope this helps you
6) Given = (i) ABCD is a ractangle
(ii) BC = 6 cm ( therefore AD = 6 cm )
(iii) AB = 8 cm
solution = in ractangle ABCD
angle A = 90° ( right angle )
angle B = 90°
angle C = 90°
angle D = 90°
in triangle ABD
angle A = 90°
by Pythagorean theorem
hypotenuse ^2 = perpendicular ^2 + base ^2
= (BD) ^2 = (AB)^2 + (AD)^2
= (BD)^2 = 8^2 + 6^2
= (BD)^2 = 64 + 36
= (BD)^2 = 100
= BD = √100
= BD = 10 cm
hope this helps you
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