Question

please answer this question

Answer 1

(1) Given if a,b ,c are three smallest
consecutive non negative integers then Find the value of

a^3 + b^3 + c^3 - 3abc .

since , we know that three smallest consecutive non negative integers are 0, 1, 2 .

let a = 0 , b = 1 , c = 2

so now put the value of a, b and c in the Given expression :

a^3 + b^3 + c^3 - 3abc

=(0)^3 + (1)^3 + (2)^3 -3 (0)(1 )(2)

= 0 + 1 +8 - 0 = 9
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(2) Given a algebraic expression :

(4xy/ 7) + 7z

given , x = additive identiy of whole number

y = multiplicative identity of natural numbers .

and z is additive inverse of 7.
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since , we know that

(i)additive identiy of whole number=0 , so x = 0

(ii) multiplicative identity of natural numbers = 1 ,so y = 1

(iii) additive inverse of 7 = - 7, so z = - 7
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so now put these values in given algebraic expression :

(4xy/ 7 ) + 7z = [4 (0) (1)/ 7 ] + 7 (-7)

=(0 / 7 ) - 49

=0 - 49 = - 49
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Your Answers : (1) 9 , (2) - 49
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