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53.5g Fe(0H)3 means 0.5mol
according to equation
3mol NaOH is needed for 1mol FeOH3
thus 1.5mol NaOH for 0.5mol FeOH3
according to equation
3mol NaOH is needed for 1mol FeOH3
thus 1.5mol NaOH for 0.5mol FeOH3
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