Question

please answer this question

Answer 1

Take LHS from to prove and do the squaring and try to writecosA-SinA andSin2A in terms ofcosA+SinA.

Mke certain rearrangement by using the property

cos2A+Sin2A = 1

and you will get the answer.




Thanks.
.

4 years ago

CosA+SinA=​root2CosASinA=root2CosA-CosASinA=CosA(root2-1)

Multiply by (root2+1) on numerator as well as denominator

 

SinA=CosA(root2-1)(root2+1)  /   (root2+1) 

SinA=CosA(2-1)  /  (root2+1) 

SinA=CosA / (root2+1) 

CosA=SinA(root2+1) 

CosA=root2SinA+SinA

CosA-SinA=root2SinA

Thus Prooved