Question

please answer this question

Answer 1

Refer the attachment for figure


Consider the intersecting point of DB and CE as O

Now since DB is a diagonal and the figure is a square, => angle DBE = 45°

(A diagonal of a square divides the interior angles into half, that is, 45°)

and angle EOB = 75° (Vertically opposite angles)

Now in ∆EOB,

x lies exterior to angle EOB and angle OBE

so by exterior angle property of a ∆,

x = angle EOB + angle OBE

=> x = 75° + 45°

=> x = 120°

Hope it helps dear friend ☺️✌️