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HEY MATE
ACCORDING TO KAPLER'S THIRD LAW
T² IS DIRECTLY PROPORTIONAL TO R³
T²1=R³
T²2=(4R)³
T²1/T²2= 1/64
T1/T2=(1/64)^1/2
T1/T2=1/8
T²=8T1
SO AFTER TAKING SATELLITE TO 4R DISTANCE TIME BECOME 8 TIMES OF INITIAL VALUE
HOPE IT WILL HELP U
ACCORDING TO KAPLER'S THIRD LAW
T² IS DIRECTLY PROPORTIONAL TO R³
T²1=R³
T²2=(4R)³
T²1/T²2= 1/64
T1/T2=(1/64)^1/2
T1/T2=1/8
T²=8T1
SO AFTER TAKING SATELLITE TO 4R DISTANCE TIME BECOME 8 TIMES OF INITIAL VALUE
HOPE IT WILL HELP U
Answered by
0
HEY MATE HERE IS URR ANSWER
By Kepler's third law T^2 is proportional to r^3
So (T2 / T1)^2 = (r2/ r1)^3
Now T2 = ?
T1 = T
r1 = r and r2 = 4r
T2^2 = T^2 * (4)^3 = 64 T^2
Therefore T^2 = 8 T
HOPE THAT IT HELPED YOU. ..☺☺☺☺
By Kepler's third law T^2 is proportional to r^3
So (T2 / T1)^2 = (r2/ r1)^3
Now T2 = ?
T1 = T
r1 = r and r2 = 4r
T2^2 = T^2 * (4)^3 = 64 T^2
Therefore T^2 = 8 T
HOPE THAT IT HELPED YOU. ..☺☺☺☺
anshika160:
please mark as brainliest if helped
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