Question

Please answer this question

Answer 1

Let the tap with smaller diameter fills the tank alone in x hours.

Let the tap with larger diameter fills the tank alone in (x – 10) hours.

In 1 hour, the tap with smaller diameter can fill 1/x part of the tank.

In 1 hour, the tap with larger diameter can fill 1/(x – 10) part of the tank.

The tank is filled up in 75/8 hours.

Thus, in 1 hour the taps fill 8/75 part of the tank.

•••••From here the answer in the attachment ••••

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If x = 25, then (x – 10) = 25 – 10 = 15.

Thus, the tap with smaller diameter fills the tank alone in 25 hours where as the larger diameter fills the tank alone in 15 hours.
$\boxed{Hope\:it'll\:help}$
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Answer 2

Hey___Mate
Here is ur answer.

Let the time taken by the smaller taplease be x
Let the time taken by the larger tap be x-10

According to the question,
1÷x +1÷x-10 = 8÷75

(x-10)75 + (75)x = 8(x)(x-10)
75x -750 +75x=8x^2-80x


Hence, the quadratic equation is ,
8x^2 -230x+750
that is 4x^2 - 115x + 375



Now solve the equation using quadratic formula...... x=25hrs.

Time taken by larger tap is x-10 i.e 25-10 =15hrs.

Hope it helped u :))