Question

please answer this question

Answer 1

Area of trapezium =
$\frac{a + b}{2} \times h$
Whereas a = bigger base
b = smaller base
h = height
Then
A = 24.5 sq. cm
Put in formula
$24.5 = \frac{10 + 4}{2 } \times h$
$24.5 = 7h$
$h = \frac{24.5}{7}$
h = 3.5 cm
Now,
Area of a sector
$\frac{theta}{360} \times \pi \times {r}^{2}$
r = h (it is given that ABE is a quadrant of a circle)
r = 3.5 cm
Theta = 90 degree
Put in formula
$\frac{90}{360} \times \frac{22}{7} \times {3.5}^{2}$
$\frac{1}{4} \times \frac{22}{7} \times 12.25$
$\frac{1}{4} \times 22 \times 1.75$
As 12.25 divided by 7 = 1.75
$\frac{1}{4} \times 38.5$
$\frac{38.5}{4}$
$9.625$
Area of shaded region = area of trapezium - area of sector
= 24.5 - 9.625
= 14.875
It is your answer hope it will help you






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