Question

please answer this question

Answer 1

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Answer 2

Answer:

Hope this helps...

ED || QO  =>  ∠PED = ∠PQO  =>  ΔPED is similar to ΔPQO (angle at P is common)  =>  PE / PQ = PD / PO

DF || OR  =>  ∠PFD = ∠PRO  =>  ΔPFD is similar to Δ PRO (angle at P is common)  =>  PF / PR = PD / PO

Hence PF / PR = PE / PQ  =>  ΔPEF is similar to ΔPQR (angle at P is common)  =>  ∠PEF = ∠PQR  =>  EF || QR