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Step-by-step explanation:
A cone of radius CD and height AD as shown in figure is cut from the top of 4cm at point E.
now, AD = 12cm , CD = 6cm , AE = 4cm
here it is clear that ∆ABE ~ ∆ACD
so, AE/AD = BE/CD
4cm/12cm = BE/6cm
BE = 2 cm { it is the radius of small circular part , Let r }
now, whole surface area of remaining part of cone = lateral surface area of frustum + area of above circular part + area of below circular part
= πl(R + r) + πr² + π R²
where, l = √{h² + (R - r)²}
here, h = 12cm - 4cm = 8 cm
so, l = √{8² + (6-2)²} = √{64 + 16} = 4√5cm
now, whole surface area = π × 4√5 × (6 +2) + π × (6)² + π × (2)²
= 32√5π + 36π + 4π cm²
= (32√5 + 40)π cm²
= (32 × 2.236 + 40) × 22/7 cm²
= 350.59 cm²
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