Question

please answer this question

Answer 1

Answer:

8.8 cm

Step-by-step explanation:

From the given information:

Let ΔABC ~ ΔDEF such that ar(ΔABC) = 121 cm² and ar(ΔDEF) = 64 cm².

Given, AM and DN are the corresponding medians of ΔABC and ΔDEF respectively.

Given, Median of ΔABC = AM = 12.1 cm.

Let, Median of ΔDEF = DN = x cm.

∴ Ratio of areas of two similar triangles is equal to ratio of squares of their corresponding sides.

⇒ ar(ΔABC)/ar(ΔDEF) = AP²/DQ²

⇒ 121/64 = (12.1)²/x²

⇒ 121x² = (12.1)² * 64

⇒ 121x² = 9370.24

⇒ x² = 77.44

⇒ x = 8.8 cm.

Therefore, Median of ΔDEF = 8.8 cm.

Hope it helps!

Answer 2

∆ABC~∆DEF...,..........given

Now,

By similar triangle theorem we get,

∆ABC2 /∆ DEF2 = BC2 / EF2

64/121 = BC2/(15.4)2

By taking square roots of both sides,

8/11= BC/15.4

By cross multiplication,

(15.4×8)/11 = BC

BC=11.2

therefore value of is 11.2