Please answer this question
Attachments:
Answers
Answered by
0
D) 4/5
Just think in triangleABC
AC2=AB2+CB2
ANGLE ABC=90(PYTHAGORAS)
ALSO IN TRIANGLE DEC
, ANGLE EDC+DEC=90+THETA(SUM OF OPPOSITE TO INTERIORS =EXTERIOR ANGLE)
Angle DEC=90
SO EDC=THETA
TRIANGLE DEC AND ABC SIMILAR
DC/5=EC/4
EC/DC=4/5
HOPE IT WILL HELP YOU...
Just think in triangleABC
AC2=AB2+CB2
ANGLE ABC=90(PYTHAGORAS)
ALSO IN TRIANGLE DEC
, ANGLE EDC+DEC=90+THETA(SUM OF OPPOSITE TO INTERIORS =EXTERIOR ANGLE)
Angle DEC=90
SO EDC=THETA
TRIANGLE DEC AND ABC SIMILAR
DC/5=EC/4
EC/DC=4/5
HOPE IT WILL HELP YOU...
singlavansh777:
plz mark my answer as brainliest
Answered by
1
Hope this help........
Attachments:
Similar questions