Math, asked by yoyorajvirsingh99, 1 year ago

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Answered by sanjaymargale2padgh6
1
hope u understand
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Anonymous: Nyc ans Genius
Answered by Anonymous
10
We Have

 \huge \frac{1}{1 + \cos^{2} ( \alpha )} + \frac{1}{1 + \sin ^{2} ( \alpha ) } + \frac{1}{1 + \sec ^{2} ( \alpha ) } + \frac{1}{1 + \cosec ^{2} ( \alpha ) }

We Know

 \sin( \alpha ) = \frac{1}{ \csc( \alpha ) }

and

 \cos( \alpha ) = \frac{1}{ \sec( \alpha ) }

Putting This In Question, We Get

\huge \frac{1}{1 + \cos^{2} ( \alpha )} + \frac{1}{1 + \sin ^{2} ( \alpha ) } + \frac{1}{1 + \frac{1}{ \sin^{2} ( \alpha ) } } + \frac{1}{1 + \frac{1}{ \cos^{2} ( \alpha ) } }

On Solving We Get,

 \huge \red {\frac{1 + sin^{2} \alpha }{1 + sin^{2} \alpha} + \frac{1 + cos^{2} \alpha }{1 + cos^{2} \alpha} }

 \huge \blue {= 1 + 1}

 \huge \orange {= 2 }

Hence Proved :)

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