Question

please answer this question ​

Answer 1

$\mathfrak{\underline{\underline{\huge{Answer-}}}}$

Let the third zero be ${\gamma}$

GIVEN

α = 3

β = -3

As we know,

$\alpha + \beta + \gamma = \frac{ - b}{a}$

So,

$3 + (-3 )+ \gamma = \frac{ - 1}{1}$

$0 + \gamma = - 1$

$\gamma = - 1$

Hence the third zero is $\pink{-1}$