Question

please answer this question ​

Answer 1

heya your answer is here hope it helps...

given,

initial velocity=30m/s

mass of the body=2kg

force=6N

time=5sec

we know that

F=ma

a=F/m

a=6/2

a=3m/s²

distance

$s = ut + \frac{1}{2} a {t}^{2}$

s=30*5+1/2*3*5*5

s=150+37.5

s=187.5m

hope it helps...