Math, asked by monisha196294, 1 year ago

please answer this question​

Attachments:

Answers

Answered by nobodyknowsme
1

Answer:

Here is your answer.

Step-by-step explanation:

a. Total resistance in arm CE

for series connection

R=R1+R2

R= 2+4=6 ohm

b. Total Current drawn from battery

for parallel connection

R= R1*R2/R1+RE

R= 6*6/6+6=36/12=3

Rparallel= 3 ohm

V=IR

I=V/R=V/3

c. Current in arm AB

I2=V/R2

I2=V/6

Current in arm CE

I1=V/R1

I1=V/6

Similar questions