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Here is your answer.
Step-by-step explanation:
a. Total resistance in arm CE
for series connection
R=R1+R2
R= 2+4=6 ohm
b. Total Current drawn from battery
for parallel connection
R= R1*R2/R1+RE
R= 6*6/6+6=36/12=3
Rparallel= 3 ohm
V=IR
I=V/R=V/3
c. Current in arm AB
I2=V/R2
I2=V/6
Current in arm CE
I1=V/R1
I1=V/6
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