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A and B together can do a work in 20 days, B and C in 40 days, and A and C in 30 days. Who is the most efficient among the three persons?
BRAINLIEST QUESTION
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A is the most efficient among the three persons.
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A and B can do a work in 20 days.
(A + B)'s one day work = 1/20 ------(1)
B and C can do a work in 40 days.
( B +C)'s one day work = 1/40 -----(2)
C and A can do a work in 30 days.
( A + C)'s one day work = 1/30 -----(3)
On adding equation 1, 2 and 3, we get
( A + B + B + C + C + A) = 1/20 + 1/40 + 1/30
=> 2 ( A + B + C) = ( 6 + 3 + 4) / 120
=> A + B + C = 13 / 240 ------(4)
On subtracting equation 1 from 4, we get
C' s one day work = 13 / 240 - 1 /20
= ( 13 - 12) / 240
= 1/240
C can do the work alone in 240 days.
Now,
On subtracting equation 2 from 4, we get
A's one day work = 13 /240 - 1 /40
= ( 13 - 6) / 240
= 7 / 240
A can do the work in 240/7 = 34.29 days
Now,
On subtracting equation 3 from 4, we get
B's one day work = 13/240 - 1/30
= ( 13 - 8) / 240
= 5 / 240
= 1 / 48
B can do the work in 48 days.
So,
The most efficient is A
(A + B)'s one day work = 1/20 ------(1)
B and C can do a work in 40 days.
( B +C)'s one day work = 1/40 -----(2)
C and A can do a work in 30 days.
( A + C)'s one day work = 1/30 -----(3)
On adding equation 1, 2 and 3, we get
( A + B + B + C + C + A) = 1/20 + 1/40 + 1/30
=> 2 ( A + B + C) = ( 6 + 3 + 4) / 120
=> A + B + C = 13 / 240 ------(4)
On subtracting equation 1 from 4, we get
C' s one day work = 13 / 240 - 1 /20
= ( 13 - 12) / 240
= 1/240
C can do the work alone in 240 days.
Now,
On subtracting equation 2 from 4, we get
A's one day work = 13 /240 - 1 /40
= ( 13 - 6) / 240
= 7 / 240
A can do the work in 240/7 = 34.29 days
Now,
On subtracting equation 3 from 4, we get
B's one day work = 13/240 - 1/30
= ( 13 - 8) / 240
= 5 / 240
= 1 / 48
B can do the work in 48 days.
So,
The most efficient is A
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