Question

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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Question

$\sf \dfrac{ {2}^{3x - 1 } + 10}{7} = 6$

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

$\sf \dfrac{ {2}^{3x - 1 } + 10}{7} = 6$

$\sf \longmapsto {2}^{3x - 1} + 10 = 7 \times 6$

$\sf \longmapsto {2}^{3x - 1} + 10 = 42$

$\sf \longmapsto {2}^{3x - 1} = 42 - 10 = 32$

[2⁵=2×2×2×2×2=32]

$\sf \longmapsto {2}^{3x - 1} = {2}^{5}$

Same bases on both sides ,so 2 automatically gets cancelled.

$\sf \longmapsto3x - 1 = 5$

$\sf \longmapsto3x = 6$

$\sf \longmapsto \: x = 2$

$\sf \large \bold{{ \red{x = 2}}}$

Check

$\sf \longmapsto \dfrac{ {2}^{3(2) - 1} + 10}{7} = 6$

$\sf \longmapsto \dfrac{ {2}^{5} + 10 }{7}$

$\sf \longmapsto \dfrac{32 + 10}{7}$

$\sf \longmapsto \dfrac{42}{7} = 6$