Math, asked by balasahebdan, 6 months ago

Please answer this question and find 1. X 2. angle BAC 3. angle ACB

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Answers

Answered by hemalatahiremath1972
1

Answer:

x = 50° ; Angle BAC = 350° ; Angle ACB = 300°

Step-by-step explanation:

1. x = 180° - 130°

= 50°

2. Angle BAC = 7x

= 7 × 50°

= 350°

3. Angle ACB = 6x

= 6 × 50°

= 300°

Answered by bnida0392
0

Answer:

DBC = BAC + BCA ( exterior angle property of triangle )

so, 130 = 7x + 6x

130 = 13x

130/13 = x

10 = x

X= 10

BAC = 7 × 10 = 70

ACB = 6 × 10 = 60

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