please answer this question and give useless answers....
I will follow them
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(2y-10)°=(3y+ 20)°. ( interior angles)
2y-3y= 20+ 10
- y=30
y = - 30
putting the value
(2y-10)° = (2×-30-10)°=-60-10= -70
(3y+20)°=(3×-30+20)°=-90+20= -70
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nope I won't report...
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