Question

please answer this question and I will mark you as brainlist Jai shree ram ​

Answer 1

Given:-

$\mathbf{(x-4)\ is\ a\ factor\ of\ 2x^3-3x^2-18x+a}$

To find:-

$\text{The value of `a'.}$

Solution:-

$\text{Zero of (x-4):}\\\bold{(x-4)=0\\\\}\\\implies\bold{x=4}$

$\text{Putting the value of x as 4 in the given polynomial, for which the result will be 0.}$

$\mathbf{2(4)^3-3(4)^2-18(4)+a=0}\\\mathbf{\implies (2*64)-(3*16)-72+a=0}\\\mathbf{\implies 128-48-72+a=0}\\\mathbf{\implies 8+a=0}\\\bold{\boxed{\implies a=-8}}$

Answer 2

Answer:

Given:-

\mathbf{(x-4)\ is\ a\ factor\ of\ 2x^3-3x^2-18x+a}(x−4) is a factor of 2x

3

−3x

2

−18x+a

To find:-

\text{The value of `a'.}The value of ‘a’.

Solution:-

\begin{gathered}\text{Zero of (x-4):}\\\bold{(x-4)=0\\\\}\\\implies\bold{x=4}\end{gathered}

\text{Putting the value of x as 4 in the given polynomial, for which the result will be 0.}Putting the value of x as 4 in the given polynomial, for which the result will be 0.

\begin{gathered}\mathbf{2(4)^3-3(4)^2-18(4)+a=0}\\\mathbf{\implies (2*64)-(3*16)-72+a=0}\\\mathbf{\implies 128-48-72+a=0}\\\mathbf{\implies 8+a=0}\\\bold{\boxed{\implies a=-8}}\end{gathered}

2(4)

3

−3(4)

2

−18(4)+a=0

⟹(2∗64)−(3∗16)−72+a=0

⟹128−48−72+a=0

⟹8+a=0

⟹a=−8

Step-by-step explanation:

please mark this answers as brainlist please please please