Question

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Answer 1

Percentage of oxygen=27.6Precentage of metal=100-27.6=72.4Formula of the metal oxide=M3O4Let the atomic mass of the metal= xPercentage by weight of the metal in the oide M3O4=3x *100/3x+64=72.43x=0.724*3x+0.724*640.828x=46.336x=56The atomic mass of the metal=56 Element Precentage Atomic Mass Atomic ratio Simplest ratio whole no.ratioM 70 56 70/56=1.25 1.25/1.25=1 2O 30 16 30/16 1.88/1.25=1.5 3 M2O3

Answer 2

Answer:

Percentage of oxygen=27.6

Precentage of metal=100-27.6=72.4

Formula of the metal oxide=M3O4

Let the atomic mass of the metal= x

Percentage by weight of the metal in the oxide M3O4= 3x*100/3x+64= 72.43x= 0.724*3x+0.724*640.828x= 46.336x= 56

The atomic mass of the metal= 56

Element Precentage Atomic Mass Atomic ratio

Simplest ratio whole no. ratio = M 70 56 70/56=1.25 1.25/1.25=1 2O 30 16 30/16 1.88/1.25=1.5 3 M2O3

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Explanation: