Question

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answer should be 183.63 cm^2

Answer 1

Answer:

Step-by-step explanation:

The required area will be

$\tt{Ar\left(trap.\,\,ABCE\right)-Ar\left(||_{gm}\,\,GHDE\right)-Ar\left(semicircle\,\,\,BCOB\right)}$

$\tt{=\dfrac{1}{2}\times\left(25+15\right)\times24-13\times16-\dfrac{1}{2}\times\pi\times\left(\dfrac{15}{2}\right)^2}$

$\tt{=\dfrac{1}{2}\times40\times24-208-\dfrac{1}{2}\times\pi\times\dfrac{225}{4}}$

$\tt{=40\times12-208-\dfrac{225\times3.142}{8}}$

$\tt{=480-208-\dfrac{706.95}{8}}$

$\tt{=272-88.36875}$

$\tt{=186.63\,\,\,cm^2}$