please answer this question and plz explain how did u do it
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SEE,
THERE IS AN IDENTITY (x+y+z)²=x²+y²+z²+2xy+2yz+2zx
we will apply that identity
we know that square of any negative number will be positive so it is of no use.
but in the q the negative terms are -2ab and -2bc
both have b common that means b is negative.
so the correct ans is option (c)
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