Math, asked by dharun1, 1 year ago

Please answer this question Anny?

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Answered by shruti256
3
let angle ZQX be x .........(i)
so angle ZXQ will be 90-x (by angle sum property)
similarly angle ZXP will be x (from i)
and angle XPZ will be 90-x

now in triangle QZX and XZP
angle QZX=XZP (90 each)
angle ZQX=ZXP (x)
triangle QZX ~ XZP
QZ/XZ=ZX/ZP
by cross multiplication
QZ×ZP=ZX×ZX
QZ×ZP=ZX^2
hence proved....
Answered by Anny121
4
HEY , HERE'S THE ANSWER ⏫

According to the question , the answer can be solved by first showing ∆PZX ~ ∆XPZ

OPEN THE ATTACHMENT TO SEE THE STEPS

HOPE IT HELPS YOU ✌️!!

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