Question

Please answer this question Anny?

Answer 1

let angle ZQX be x .........(i)
so angle ZXQ will be 90-x (by angle sum property)
similarly angle ZXP will be x (from i)
and angle XPZ will be 90-x

now in triangle QZX and XZP
angle QZX=XZP (90 each)
angle ZQX=ZXP (x)
triangle QZX ~ XZP
QZ/XZ=ZX/ZP
by cross multiplication
QZ×ZP=ZX×ZX
QZ×ZP=ZX^2
hence proved....

Answer 2

HEY , HERE'S THE ANSWER ⏫

According to the question , the answer can be solved by first showing ∆PZX ~ ∆XPZ

OPEN THE ATTACHMENT TO SEE THE STEPS

HOPE IT HELPS YOU ✌️!!