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let angle ZQX be x .........(i)
so angle ZXQ will be 90-x (by angle sum property)
similarly angle ZXP will be x (from i)
and angle XPZ will be 90-x
now in triangle QZX and XZP
angle QZX=XZP (90 each)
angle ZQX=ZXP (x)
triangle QZX ~ XZP
QZ/XZ=ZX/ZP
by cross multiplication
QZ×ZP=ZX×ZX
QZ×ZP=ZX^2
hence proved....
so angle ZXQ will be 90-x (by angle sum property)
similarly angle ZXP will be x (from i)
and angle XPZ will be 90-x
now in triangle QZX and XZP
angle QZX=XZP (90 each)
angle ZQX=ZXP (x)
triangle QZX ~ XZP
QZ/XZ=ZX/ZP
by cross multiplication
QZ×ZP=ZX×ZX
QZ×ZP=ZX^2
hence proved....
Answered by
4
HEY , HERE'S THE ANSWER ⏫
According to the question , the answer can be solved by first showing ∆PZX ~ ∆XPZ
OPEN THE ATTACHMENT TO SEE THE STEPS
HOPE IT HELPS YOU ✌️!!
According to the question , the answer can be solved by first showing ∆PZX ~ ∆XPZ
OPEN THE ATTACHMENT TO SEE THE STEPS
HOPE IT HELPS YOU ✌️!!
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