Question

please answer this question answer

Answer 1

Hey here is your answer

your question is :-

$If \: \frac{x}{y} = \frac{3}{4} \: \: then \: the \: value \: of \\ \\ ( \frac{6}{7} + \frac{y - x}{y + x} )\: equals \: \: : -$

ANSWER :-

$\frac{x}{y} = \frac{3}{4} \\ \\ \frac{1}{y} = \frac{3}{4x} \\ \\ y = \frac{4x}{3} \: \: \: \: \: - (1) \\ \\ to \: find \: \\ \\ ( \frac{6}{7} + \frac{y - x}{y + x} )\\ \\ putting \: y \: = \frac{4x}{3} \: in \: equation \: \\ \\ ( \frac{6}{7} + \frac{(\frac{4x}{3} ) - x}{(\frac{4x}{3} ) + x} ) \\ \\ ( \frac{6}{7} + \frac{ (\frac{4x - 3x}{3} )}{(\frac{4x + 3x}{3} )} ) \\ \\ ( \frac{6}{7} + \frac{ \frac{x}{3} }{ \frac{7x}{3} } ) \\ \\ ( \frac{6}{7} + \frac{x}{3} \times \frac{3}{7x} ) \\ \\ ( \frac{6}{7} + \frac{1}{7} ) \\ \\ \frac{6 + 1}{7} \\ \\ \frac{7}{7} \\ \\ 1$

So, the answer of this question is 1.

hope this helps you

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Answer 2

it's answer is 1 because
x/y=3/4
x=3
y=4

put. value of x and y in given problem
6/7+1/7
after LCM
6+1/7
7/7
1