Question

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Answer 1

Answer:

Equation is 3+√6/3-√6 = a+b√6 then find value of 'a' and 'b'.

3+√6/3-√6 = a+b√6

(3+√6)/(3+√6)×(3+√6)/(3+√6) = a+b√6

(3+√6)^2 /(3)^2 - (√6)^2 = a+b√6

Now use this identity (a+b)^2

(3)^2+2×3×√6+(√6)^2 /9-6 = a+b√6

Solve this equation

9+6√6+6 /3 = a+b√6

15+6√6 /3 = a+ b√6

At last take LCM

15/3+6/3 √6 = a+b√6

then √6 and √6 cancel from each other

So the equation left is 15/3+6/3 = a+b

So value of a is 15/3 after divide value of a is 5 and value of b is 6/3 after divide value of b is 2

HOPE IT HELP YOU!