Question

Please answer this question as fast as possible

Answer 1

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Answer 2

Given:

Polynomial p(x)=x-2x³+3x²-ax+3a-7 which gives remainder 19 when divided by x+1

To Find:

. Value of 'a'

• Value of remainder when p(x) is divided by

x+2

Solution:

Dividend=x^-2x³+3x²-ax+3a-7

Divisor= x+1

Remainder-19

On dividing x¹-2x³+3x²-ax+3a-7 by x+1, we get

(Calculation in First attachment)

Remainder-4a-1

Also, it is given that

Remainder-19

→ 4a-1= 19

→ 4a= 20

→ a= 5

Now, after putting value of a in dividend, we get

Dividend= x¹-2x³+3x²-(5)x+3(5)-7

Dividend= x¹-2x³+3x²-5x+15-7

Dividend= x¹-2x²+3x²-5x+8

Now,

Dividend=x²-2x³+3x²-5x+8

Divisor=x+2

After dividing x¹-2x³+3x²-5x+8 by x+2, we get

(Calculation in second attachment)

Remainder-62

Hence, the value of a is 5 and required remainder is 62.

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